2x^2-25x+80=0

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Solution for 2x^2-25x+80=0 equation:


Simplifying
2x2 + -25x + 80 = 0

Reorder the terms:
80 + -25x + 2x2 = 0

Solving
80 + -25x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
40 + -12.5x + x2 = 0

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -12.5x + -40 + x2 = 0 + -40

Reorder the terms:
40 + -40 + -12.5x + x2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -12.5x + x2 = 0 + -40
-12.5x + x2 = 0 + -40

Combine like terms: 0 + -40 = -40
-12.5x + x2 = -40

The x term is -12.5x.  Take half its coefficient (-6.25).
Square it (39.0625) and add it to both sides.

Add '39.0625' to each side of the equation.
-12.5x + 39.0625 + x2 = -40 + 39.0625

Reorder the terms:
39.0625 + -12.5x + x2 = -40 + 39.0625

Combine like terms: -40 + 39.0625 = -0.9375
39.0625 + -12.5x + x2 = -0.9375

Factor a perfect square on the left side:
(x + -6.25)(x + -6.25) = -0.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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